This process for reversing the Product Rule for Derivatives is called Integration by Parts . It is covered in Section 14.2. In Integration by Parts, the integrand (the thing you are finding the antiderivative of) is written as a product. One piece is thought of as u and the other part v‘. The formula then says
$latex \int{u{v}’ dx=uv-\int{v{u}’ dx}}$
Below are several examples that students worked out.
Problem 1 –
$latex \displaystyle \int{\left( 1-x \right){{e}^{x}} dx}$
Problem 2 –
$latex \displaystyle \int {\left( 8x+10 \right) \ln \left( x \right) dx}$
$latex \displaystyle \int{\left( 2t-1 \right) \ln \left( t \right) dt}$