Death and Piecewise Linear Functions

Although this may seem a little gruesome, it is not uncommon for businesses to give discounts for volume sales. In this case, a mortician charges less per pound for bodies weighing more than a certain amount.

The local mortician charges by the pound for embalming according to the following table:

piecewise_lin_death_01

Find a piecewise linear function that models the cost as a function of weight.

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Rates and Rational Models

pe_quotient_ruleMany situations require us to take the derivative of a quotient. One situation like this is a model of a stocks price to earning ratio. In this situation the price is modeled by a function P(t) and the earnings by E(t).To find the rate at which the PE ratio is changing, you need to need to take the derivative of the model for the PE ratio.

The ratio is modeled by a quotient, P(t)/E(t). Since this is a quotient, we need to apply the quotient rule for derivative, pe_quo_01

but apply this to our functions. This means u will be replaced with P and v will be replaced with E to give

pe_quo_02

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How Do You Find The Equation Of A Tangent Line?

A tangent line to a function is a line that looks most like the function at a point. In common terms, it just grazes the function.

eqn_tan_2

To find its equation, we need to locate the point where the two meet as well as the slope of the function at that point. Then we can use the slope-intercept form or point-slope form of a line to get the equation.

Find the equation of the tangent line to

eqn_tan__3

at x = 3.

Since this problem is asking for the equation of a line, let’s start with the point-slope form

eqn_tan__4

This requires a point (x1, y1) and slope m. We’ll use the function to get the point and the derivative to get the slope of the tangent line.

Find the point: We are given a point x = 3. To find the corresponding y value, put the x value into the function

eqn_tan__5

Find the slope of the tangent line: We need h′(3) to get the slope of the tangent line. We’ll use the Power Rule to take the derivative,

eqn_tan__6

The slope of the tangent is

eqn_tan__7

Write the equation of the tangent line: Putting the point (3, 10) and the slope 9 into the line yields

eqn_tan__8

If you are asked to write this in slope-intercept form, you’ll need to solve this for y to give

eqn_tan__9

If you graph h(x) and the tangent line together, it should be obvious that your tangent line is correct (ie. tangent).

eqn_tan_2